100 Contemporary Wood Buildings (Bibliotheca Universalis) (Multilingual Edition)

100 Contemporary Wood Buildings (Bibliotheca Universalis) (Multilingual Edition)

Matematika tolong bantu beserta caranya dan konsepnya ​

tolong bantu beserta caranya dan konsepnya ​

Jawaban:

1.

mis total tiket = x

penjualan hr ke1 = 24

sisa hr ke1 = x-24

penjualan hr ke2 = ⅔(x-24)

penjualan hr ke3 = 6

total tiket = penjualan hr ke1 + ke2 + ke3

x = 24 + ⅔(x-24) + 6

x = ⅔x + 24 - 16 + 6

⅓x = 14

x = 42 tiket

2.

* utk halaman 1-69, 80-169, 180-263: tiap 10 halaman muncul angka 7 sekali

* utk halaman 70-79, 170-179: tiap 10 halaman muncul angka 7 11kali

hal 1-69 : 7 kali

hal 70-79 : 11 kali

hal 80-169 : 9 kali

hal 170-179 : 11 kali

hal 180-263 : 8 kali

Total. : 46 kali

3. rumus teleskopik:

[tex] \frac{1}{ {n}^{2} + n} = \frac{1}{n} - \frac{1}{n + 1} [/tex]

[tex] \frac{1}{ {1}^{2} + 1 } = \frac{1}{1} - \frac{1}{2} [/tex]

[tex] \frac{1}{ {2}^{2} + 2} = \frac{1}{2} - \frac{1}{3} [/tex]

dst

maka persamaan di atas akan menjadi

[tex] \frac{1}{1} - \frac{1}{2} + \frac{1}{2} - \frac{1}{3} + \frac{1}{3} - \frac{1}{4} + \frac{1}{4} - \frac{1}{5} + ... + \frac{1}{2009} - \frac{1}{2010} [/tex]

[tex] - \frac{1}{2} + \frac{1}{2} = 0[/tex]

[tex] - \frac{1}{3} + \frac{1}{3} = 0[/tex]

dst

sehingga yg tersisa hanya

[tex] \frac{1}{1} - \frac{1}{2010} [/tex]

[tex] = \frac{2009}{2010} [/tex]

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